BINOM.INV

BINOM.INV(trials, probability_s, alpha)

Returns the number of trials needed for a specific amount of success using a binomial distribution.

trialsThe total number of trials.
probability_sThe probability of a success on each trial.
alphaThe cumulative probability you want to find.

REMARKS
* This function was added in Excel 2010 to replace the CRITBINOM function.
* For an illustrated example refer to the page under [[Distributions]]
* The binomial distribution is a [[discrete distribution]]
* This function will return the smallest number of trials needed for which the cumulative distribution is greater than or equal to "alpha".
* If any of the arguments are not numeric, then #VALUE! is returned.
* If "trials" is not an integer, it will be truncated.
* If "trials" < 0, then #NUM! is returned.
* If "probability_s" < 0, then #NUM! is returned.
* If "probability_s" > 1, then #NUM! is returned.
* If "alpha" < 0, then #NUM! is returned.
* If "alpha" > 1, then #MUM! is returned.
* You can use the BINOM.DIST function to return the probability of getting a specific number of successes using a binomial distribution.
* You can use the BINOM.DIST.RANGE function to
* You can use the NEGBINOM.DIST function to
* For the Microsoft documentation refer to support.microsoft.com

 A
1=BINOM.INV(6, 0.5, 9.38%) = 1.00
2=BINOM.INV(6, 0.5, 23.44%) = 2.00
3=BINOM.INV(6, 0.5, BINOM.DIST(3, 6, 0.5, FALSE)) = 2.00
4=BINOM.INV(6, 0.5, BINOM.DIST(3, 6, 0.5, TRUE)) = 3.00
5=BINOM.INV(6, 0.5, 0.75) = 4.00
6=BINOM.INV(4, 0.5, 0.75) = 3.00
7=BINOM.INV(4, 0.5, 0.9999) = 4.00
8=BINOM.INV(4, 0.5, 0.0001) = 0.00
9=BINOM.INV(4, 0.5, -0.75) = #NUM!
10=BINOM.INV(4, -0.5, 0.75) = #NUM!


© 2024 Better Solutions Limited. All Rights Reserved. © 2024 Better Solutions Limited Top