DATEADD(interval, number, date)

Returns the date with a specified time interval added (Date).

intervalThe interval of time you want to add (String):
"yyyy","YYYY" = year
"q","Q" = quarter
"m","M" = month
"y","Y" = day of year
"d","D" = day
"w","W" = weekday
"ww","WW" = week
"h","H" = hour
"n","N" = minute
"s","S" = second
numberThe number of intervals to add (Long).
dateThe date you want the interval added to (Date).

* The "interval" is confusing, for example: "y","Y" = day of year and not years.
* If "interval" = "y" or "Y", this will add Days and not Years.
* To add years to a date, you need to use "yyyy" or "YYYY".
* The "number" can be any numeric expression.
* If "number" is not a Long, then it is rounded to the nearest whole number before getting evaluated.
* This function will never return an invalid date.
* If you subtract more time than is in the "date", then an error occurs.
* The format of the date that is returned is determined by the PC settings from the control panel.
* This function can be used to add or subtract a specified time interval from a date.
* You can use the CDATE function to return an expression converted to a Date data type.
* You can use the DATEDIFF function to return the number of a given time interval between two specified dates.
* You can use the DATEPART function to return the specified part of a given date.
* You can use the DATESERIAL function to return the date given a year, month and day.
* You can use the DATEVALUE function to return the date given a string representation of a date.
* You can use the FORMAT function to return a text string of a date in a particular format.
* You can use the NOW function to return the current system date and time.
* The equivalent .NET function is Microsoft.VisualBasic.DateAndTime.DateAdd
* For the Microsoft documentation refer to

Debug.Print VBA.Now()                                 '18/02/2024 08:53:34  
Debug.Print DateAdd("yyyy", 1, VBA.Now()) '18/02/2025 08:53:34
Debug.Print DateAdd("yyyy", 1, "01-01-2024") '01/01/2025
Debug.Print DateAdd("q", 1, "01-01-2024") '01/04/2024
Debug.Print DateAdd("m", 1, VBA.Now()) '18/03/2024 08:53:34
Debug.Print DateAdd("m", 1, "01-01-2024") '01/02/2024

'2024 is a leap year, so February has 29 days
Debug.Print DateAdd("m", 1, VBA.CDate("31 Jan 2024")) '29/02/2024

'these 3 lines all add one day
Debug.Print DateAdd("y", 1, "01-01-2024") '02/01/2024
Debug.Print DateAdd("d", 1, "01-01-2024") '02/01/2024
Debug.Print DateAdd("w", 1, "01-01-2024") '02/01/2024

'this adds 5 weekdays
Debug.Print DateAdd("w", 5, "01-01-2024") '06/01/2024

'this adds 5 weeks
Debug.Print DateAdd("ww", 5, "01-01-2024") '05/02/2024

Debug.Print VBA.Now() '18/02/2024 08:53:34
Debug.Print DateAdd("w", 2, VBA.Now()) '20/02/2024 08:53:34 (weekdays)
Debug.Print DateAdd("h", 5, VBA.Now()) '18/02/2024 13:53:34 (hours)
Debug.Print DateAdd("n", 5, VBA.Now()) '18/02/2024 08:58:34 (minutes)
Debug.Print DateAdd("s", 10, VBA.Now()) '18/02/2024 08:53:44 (seconds)

Dim lSerial As Long
lSerial = DateAdd("d", 1, "01/07/2024")
Debug.Print lSerial '45475

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