FIX

FIX(number)

Returns the integer portion of a number (data type).

number

The number (data type).

REMARKS

* The fractional/decimal part of the number is removed.
* This function is identical to the INT function for positive numbers.
* This function truncates without rounding.
* The value returned has the same data type as the value passed in.
* If "number" is Null, Null is returned.
* If "number" < 0, then the first negative integer greater than or equal to "number" is returned.
* The results from this function are equivalent to : Sgn(number) * Int(Abs(number)).
* You can use the INT function to return the number rounded down to the nearest integer.
* You can use the ROUND function to return a number rounded to a given number of decimal places.
* The equivalent .NET function is [[Microsoft.VisualBasic.Conversion.Fix]]
* For the Microsoft documentation refer to learn.microsoft.com

Debug.Print Fix(-8.9)   '= -8  
Debug.Print Fix(-8.4)   '= -8  
Debug.Print Fix(-8.1)   '= -8  
Debug.Print Fix(-7.9)   '= -7  
Debug.Print Fix(-1.9)   '= -1  
Debug.Print Fix(-1.1)   '= -1  
Debug.Print Fix(-0.1)   '= -0  
Debug.Print Fix(0.2)    '= 0   
Debug.Print Fix(0.5)    '= 0   
Debug.Print Fix(0.6)    '= 0   
Debug.Print Fix(0.9)    '= 0   
Debug.Print Fix(1.1)    '= 1   
Debug.Print Fix(1.5)    '= 1   
Debug.Print Fix(12.01)  '= 12   
Debug.Print Fix(12.34)  '= 12   
Debug.Print Fix(12.99)  '= 12  

Dim iInteger As Integer 
iInteger = 20 
Debug.Print TypeName(Fix(iInteger))  '= Integer  

Dim lLong As Long 
lLong = 20.5 
Debug.Print TypeName(Fix(lLong))     '= Long  

Dim dbDouble As Double 
dbDouble = 20.5 
Debug.Print TypeName(Fix(dbDouble))  '= Double