VBA Function INSTR

INSTR([start] ,string1 ,string2 [,compare])

Returns the position of a substring within a larger string (Long).

start	(Optional) The character position to start searching from (Integer).
string1	The text string containing your substring (String).
string2	The text string to look for (String).
compare	(Optional) A vbCompareMethod constant specifying the type of string comparison to use (Integer): -1 = vbUseCompareOption (uses the "Option Compare" setting) 0 = vbBinaryCompare (default, case sensitive) 1 = vbTextCompare 2 = vbDatabaseCompare (uses an Access database)

REMARKS

* This is case sensitive by default.
* If "start" is left blank, then 1 is used. (i.e. you start searching from the first character).
* If "start" is 0, then a run-time error occurs.
* If "start" is Null, then an error occurs.
* If "string1" cannot be found in "string2" then 0 is returned.
* If "string1" = "string2" or "string1" is the beginning of "string2" then 1 is returned.
* If "compare" is left blank, then -1 is used. If there is no Option Compare statement provided then vbBinaryCompare (0) is used.
* If "compare" is null, then an error occurs.
* You can use the INSTRREV function to start at the end.
* You can use the INSTR$ function to return a String data type instead of Variant/String data type.
* If you type in INSTR$ with valid arguments the editor will automatically change this function to just INSTR.
* You can use the INSTRB function that is used with byte data.
* For more information, refer to the Finding Strings page.
* The equivalent .NET function is Microsoft.VisualBasic.Strings.InStr
* For the Microsoft documentation refer to docs.microsoft.com

InStr("C:\Temp\","C:\") = 1 
InStr(1,"C:\Temp\","C:\") = 1 
InStr(1,"C:\Temp\","E:\") = 0 
InStr(1,"somemoretext","more") = 5 
InStr("somemoretext","more") = 5 
InStr("somemoretext","somemoretext") = 1 
InStr("somemoretext","nothing") = 0