BINOM.INV(trials, probability_s, alpha)

Returns the number of trials needed for a specific amount of success using a binomial distribution.

trialsThe total number of trials.
probability_sThe probability of a success on each trial.
alphaThe cumulative probability you want to find.

* This function was added in Excel 2010 to replace the CRITBINOM function.
* For an illustrated example refer to the page under [[Distributions]]
* The binomial distribution is a [[discrete distribution]]
* This function will return the smallest number of trials needed for which the cumulative distribution is greater than or equal to "alpha".
* If any of the arguments are not numeric, then #VALUE! is returned.
* If "trials" is not an integer, it will be truncated.
* If "trials" < 0, then #NUM! is returned.
* If "probability_s" < 0, then #NUM! is returned.
* If "probability_s" > 1, then #NUM! is returned.
* If "alpha" < 0, then #NUM! is returned.
* If "alpha" > 1, then #MUM! is returned.
* You can use the BINOM.DIST function to return the probability of getting a specific number of successes using a binomial distribution.
* You can use the BINOM.DIST.RANGE function to
* You can use the NEGBINOM.DIST function to
* For the Microsoft documentation refer to

1=BINOM.INV(6,0.5,9.38%) = 1.00
2=BINOM.INV(6,0.5,23.44%) = 2.00
3=BINOM.INV(6,0.5,BINOM.DIST(3, 6,0.5,FALSE)) = 2.00
4=BINOM.INV(6,0.5,BINOM.DIST(3, 6,0.5,TRUE)) = 3.00
5=BINOM.INV(6,0.5,0.75) = 4.00
6=BINOM.INV(4,0.5,0.75) = 3.00
7=BINOM.INV(4,0.5,0.9999) = 4.00
8=BINOM.INV(4,0.5,0.0001) = 0.00
9=BINOM.INV(4,0.5,-0.75) = #NUM!
10=BINOM.INV(4,-0.5,0.75) = #NUM!

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